1
929views
0
6views
written 5.7 years ago by |
Circuit Realization using pass transistor logic:
- $2^n:1$ MUX using pass transistor,
- Implement 2 : 4 decoder using pass transistor logic,
D- Flip-Flop using Pass transistor:-
Master- slave D-F/F:-
Transmission Gate logic:-
Region I | Region II | Region III |
---|---|---|
nMOS sat | nMOS sat | nMOS cut-off |
pMOS sat | pMOS lin | pMOS lin |
nMOS $V_{DSn} = V_{DD} - V_{out}$
$V_{GSn} = V_{DD} - V_{out}$
nMOS will turn-off when $V_{out} \gt V_{DD} - V_{TD}$
nMOS will remain in saturation for $V_{out} \lt V_{DD} - V_{TD}$
pMOS $V_{OSp} = V_{out} - V_{DD}$
$V_{GSn} = -V_{DD}$
pMOS in saturation for $V_{out} \lt |V_{Tp}|$
& in linear for $V_{out} \gt |V_{Tp}|$
A -> B When A = 0 through nMOS
A -> B When A = 1 through pMOS
$I_D = I_{DSp} + I_{DSn}$
C = 1 = $V_{DD}$ Both transistors ON-Low Reg path
c = 0 -> Both OFF -> High Impedence
OR Gate:
AND Gate:
XOR Gate:
XNOR Gate:
NAND Gate:
NOR Gate:
ADD COMMENT
EDIT
Please log in to add an answer.