written 5.8 years ago by |
The shear stress for laminar or viscous flow is given by Newton's law of viscosity as:-
$\tau_v=\mu\dfrac{du}{dy}$
Similarly for the expression of viscous shear, J. Bossinesq expressed the turbulent shear in mathematical form as,
$\tau_t=\eta\dfrac{d\overline{u}}{dy}.............................(1)$
Where,
$\tau_t$ = Shear stress due to turbulence
$\eta$ = Eddy viscosity
$\overline{u}$ = Average velocity at a distance y from boundary.
The ratio Eddy viscosity and $\rho$ (mass density) is known as kinematics Eddy viscosity and is denoted by $\varepsilon $ (epsilon).
$\varepsilon=\dfrac{\eta}{\rho}$
Now, if the shear stress due to laminar flow is also considered, then the total shear stress becomes,
$\tau=\tau_v+\tau_t$
$\tau=\mu\dfrac{du}{dy}+\eta\dfrac{d\overline{u}}{dy}$
$\eta=0$ (for laminar flow). For other cases the value of ‘$\eta$’ may be several thousand times the value of ‘$\mu$’.
To find shear stress in turbulent flow equation (1) is used. But since the value of ‘$\eta$’ cannot be predicted, this equation is having limited use.