written 6.1 years ago by |
Given
w=56kN/m
factored load =56×1.5=84kN/m
length of span=2m
Required =design laterally unsupported beam
1) V=wd2=84×22=84kN
m=wl28=84×228=42kN.m
2) Trial section
Zpreq=Mfbd
Assume λ=100 htf=25mm
fcrb=291.4 Md
250 152.3
291.4 fbd
300 163.6
fbd=161.65
Zpreq=42×106161.65
Zpreq=259.82×103mm3
ISMB 200
Zp=255.36×103
D=200 bf=100mm tf=10.8mm
tw=5.7mm γ xx=83.2
γyy=21.5 Ixx=2235.4×106mm4
Zxx=224×103 R1=11mm
Dtf=20010.8=18.52
kLγmin=200021.5=93
18 18.5220
90 402.2 x 380.4
93 x y
100 34364 325.8
18 402.2
18.52 x
20 380.4
18 346.4
18.52 y
20 325.8
x=396.53 y=341.64
90 396.53
93 fcr
10 341.04
fcrb=379.88
350 172.7
379.88 fbd
400 184.1
fbd=179.21mpa
md=Bd∗ZP∗fbd
=1∗(255.56)×179.89
=45.94kN > m(42)
Anaysis is safe