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Design of purlin given 10 span=4m 2)spacing =1.72m 3)θ=304∘
1 Answer
written 6.1 years ago by |
load calculation
D.L/---weight of GI sheet= 150Pa
self weight at purlin=100 ,pa
Total DL=250Pa=0.25Kpa
plan Area=1.73×cos30∘=1.5m
D.L on Plan area =0.25× 1.5=0.375kN/M
L.L--L.L on plan =0.4 ×1.5=0.6kN/m
W.L--W.L on sloping Area=0.723×1.73=-1.31 kN
Load Normal to slope Zz
Wdz=0.375×cos30∘
= 0.325 kN/m
WLz=0.6×10530∘
=0.52KN/m
Total …