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Design wind pressure Pd=n.6×Vz2=0.6×35.492=755.72 PA
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written 6.1 years ago by |
Given
h=6m[height upto eaves]
width w=9m
Ratio hw=69=0.67
AS per table 11≤hw≤32
i] wind perpendicular to ridge [wind word]
WL1=(-0.2-0.2)×755.72= -302.29... Pa
WL2=(-0.2+0.2)× 755.72=0
ii) Wind perpednicular to ridge [Lee wared]
WL3=(-0.5-0.2)×755.72= -529.0 Pa
WL4=(−0.5+0.2]×755.72= - 226.72 Pa
iii) Wind parallel to ridge[wind ward]
WL5=(−0.8−0.2)×755.72= - 7555.72
WL6=(-0.8+0.2)× 755.72 = -453.43 PAd
iv) Wind parallel to ridge(Lee ward)
WL7=(-0.8-0.2)× 755.72 = -755.72Pa
WL8=(-0.8+0.2)× 755.72= -453.43Pa
Max wind pressure = -755.72 Pa
= -0.756 KPa( Uplift or section]
Total wind load on each intermedaite panel point
= -755.72 × sloping Area
= - 755.72×[1.73×4]
= -522.9.58 N
= -5.24kN
Total wind load on each end panel point
= -5.242= -2.62 kN
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