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Detemine factor Udl on laterally unsupported beam ISLB 300 of span 3.25m s.s at the ends
Given ISLB 300
D=300 bw=150 tf=9.4
tw=6.7 γ1=15
Ze=488.9×103
Iz=7332.9×104mm4
Iy=376.2×104mm4
Zp=554.32×103mm4-- Is code
span length =3250mm
d=300-2×9.4−2×15=251.2
1) sectional classification
btf=bf/2tf=7.98< 9.4 ϵ
dtw=D−2tf−2R16.7=251.26.7=37.49<84ϵ
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