written 5.7 years ago by |
is 200mm top flange embedded in concrete unit weight of concrete is 25 kN/m$^{3}$
3) L.L on slab is 3kN/m$^{2}$ and F.F=1kN/m$^{2}$
Given
L.L=3kN/m$^{2}$
F.F=1kN/m$^{2}$
$\frac{ly}{lx}=\frac{6.5}{3}=2.167\gt$2 one way slab
load on beam=slab load+wall load+weight of beam
Slab load
Concrete load=25$\times$3$\times$0.2=15kN/m
Floor finish load=1$\times$3=3kN/m
Live load=3$\times$3=9kN/m
factor load=27$\times$1.5=40.5kN/m
Wall load
20$\times$0.230$\times$4=18.4kN/m
factored wall load=18.4$\times$1.5=27.6kN/m
Weight of beam
1kN/m
factored weight of beam=1$\times$1.5=1.5kN/m
load on beam=40.5+27.6+1.5
=69.6kN/m
load on beam B=Slab load+wall load+self weight
=0+27.6+1.5
=29.1 kN/m
1) V=shear force=$\frac{w1}{2}+\frac{w2\times l}{2}$
=$\frac{226.2}{2}+\frac{29.1\times6}{2}$
v=200.4kN
m$\frac{w_{1}L}{4}+\frac{w_{2}l^{2}}{8}$
m=470.25kN.m
2) Trial section
Zpreq=$\frac{m\ast \gamma mo}{fy}$
=$\frac{470.25\times 1.1}{250}$
=2069.1$\times 10^{3}mm^{3}$
select ISMB 500 having Zp=2074.67$\times 10^{3}mm^{3}$
fwc=(75+85.5)$\ast 10.2\ast\frac{250}{1.1}$
=372.67kN$\gt$ 200.4kN safe
Deflection
permissible =$\frac{span}{300}=\frac{4000}{300}$=20mm
act=$\frac{w_{1}l^{3}}{48EI}+\frac{5w_{2}l^{4}}{384 EI}$
$\int$act =36.2
$\int$act=3.2$\lt$ sper safe