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Design beam B of typical flooring plan of steel building as shown following data for design 1) beam supports a brick wall of 230mm thick and 4m high having unit wt 20kN/m3 2)thickness of Rcc
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is 200mm top flange embedded in concrete unit weight of concrete is 25 kN/m3

3) L.L on slab is 3kN/m2 and F.F=1kN/m2

enter image description here

Given

L.L=3kN/m2

F.F=1kN/m2

lylx=6.53=2.167>2 one way slab

load on beam=slab load+wall load+weight of beam

Slab load

Concrete load=25×3×0.2=15kN/m

Floor finish load=1×3=3kN/m

Live load=3×3=9kN/m

factor load=27×1.5=40.5kN/m

Wall load

20×0.230×4=18.4kN/m

factored wall load=18.4×1.5=27.6kN/m

Weight of beam

1kN/m

factored weight of beam=1×1.5=1.5kN/m

load on beam=40.5+27.6+1.5

=69.6kN/m

enter image description here

load on beam B=Slab load+wall load+self weight

=0+27.6+1.5

=29.1 kN/m

enter image description here

1) V=shear force=w12+w2×l2

=226.22+29.1×62

v=200.4kN

mw1L4+w2l28

m=470.25kN.m

2) Trial section

Zpreq=mγmofy

=470.25×1.1250

=2069.1×103mm3

select ISMB 500 having Zp=2074.67×103mm3

fwc=(75+85.5)10.22501.1

=372.67kN> 200.4kN safe

Deflection

permissible =span300=4000300=20mm

act=w1l348EI+5w2l4384EI

act =36.2

act=3.2< sper safe

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