Step I

List bolt value

Shera capacity of bolt=$\frac{fub\times Anb\times hn}{\sqrt{3}\times ymb}$

=400

bolt value=29 kN

Step II

Direct shera force=$\frac{f}{4(no.of \ bolt)}$=0.25p

Step III

force in bolt due to tortion

F2=$\frac{\sum(P.e)rn}{\gamma ^{2}}$

$\sum P.e=Pcos\theta$(60-80)+Psin(150+60)

$\gamma n=\sqrt{60^{2}+60^{2}}$=84.85

$\gamma =(4\times 60^{2})+(4\times 60^{2}$=28800

F2=$\frac{pcos\theta(30)+Psin\theta(210)\times 84.85}{28800}$

F2=$\frac{pcos\theta(30)+psin\theta(210)\times84.85}{28800}$

F2=0.5P

Step IV

used resultant flow equation

R=F1+F2

2g=$\frac{p}{4}+(0.5P)$

P=38.67kN ultimate load

Step IV

Safe working load=$\frac{p}{1.5}$

$\frac{38.67}{1.5}$

=25.77kN