Type I - when bolt group are subjected to shear moment in their shear plain the load that is ecentric with respective to centroid of the bold group can be replace with a force acting through the center of bolt group and moment with the magnitude

M=P.e

p=load in kN

e= eccentric distance mm

Step i- list bolt value in single shear

Step ii direct force per bolt or load in each bolt

F1=$\frac{load}{No \ .of \ bolts}$

Step iii force in bolt due to tortion

F2=$\frac{\sum(p.e)\times \gamma n}{\sum \gamma ^{2}}$

where rn=distance between critical bolt to the CG of bolt group

r=distance of bolts from line of cg of bolt group in x & y direction

Step iv

used resultant flow equation

1)$R^{2}=F_{1}^{2}+F_{2}^{2}+2F_{1}F_{2} cos\theta$..... if point load given

2) R=F1+F2......if inclined load given

Step v- safe working load= $\frac{p}{1.5}$