Given

L=5.9m = 5900 mm

Pu=2000$\times 10^{3}$N

required two channel back to back with battern & site welding $\gamma$ mw=1.5

1. Pu=Aea$\times$ fcd

2000$\times 10^{3}$=Area$\times$ 150

Area=13333.33mm$^{2}$

Area of each section=$\frac{13333.33}{2}=6666.67mm^{2}$

provide fcd=190mpa

Pu=Area$\times$ fcd

2000$\times 10^{3}=Area\times$190

Area=1056.31mm$^{2}$

Area of each section=$\frac{10526.31}{2}$=5263.15mm$^{2}$

2) Provide ISMC 350

Aprov=5366mm$^{2}$

$\gamma$ xx=136.6mm $ …