Pu=4105$\times10^{3}$N

For m20- CFL =20mpa

Step I.

Ap=$\frac{up}{0.6\ast fck}$

=$\frac{4105}{0.6\times 20}$

Ap=342.08$\times10^{3} mm^{2}$

Assume tg=16mm

$\neq$tf

$\gt$12.7mm

Safe

Assume ISA. 150$\times$ 115$\times$15 mm

2) width of plate(sp) =400+2(200)+2(16)+2(115)+2(24)

Bp=750mm

Lp$\frac{Ap}{Bp}=\frac{342.07\times 10^{3}}{750}$

Please=456.10

L=460mm

Step II

Thickness of base plate (tp)

Bmxx= at force of angle

By=$\frac{wl^{2}}{2}$. W=$\frac{our}{Ap}=\frac{4105\times 10^{3}}{750\times 460}$

=11.9mpa$\lt$0.6fck

=11.9$\lt$12 mpa. Hence safe

Bm =$\frac{11.9\times 124^{2}}{2}$. Ze$\frac{I}{y}$

=91.49$\times 10^{3}$N mm.

d =24+(115-15)

=124

But MD zo $\ast \frac{fry}{\gamma mo}$

=(s$\ast ze)\ast \frac{fy}{\gamma mo}....s=\frac{so}{Xe}$

Md=1.12$\ast(\frac{1\ast t^{t}}{6})\ast \frac{250}{1.1.}$

Step III

Bm@ circle $\frac{wll^{2}}{8}-\frac{wl^{2}}{2}$

$\frac{11.9\times 472^{2}}{8}-\frac{11.9\times 1.39^{2}}{2}$

BMC =216.43$\times10^{3}$Nmm—-3

BMC=216.43$\times20^{3}$Nmm

MD=zp$\ast \frac{fy}{\gamma mo}$

MD=(s$\ast ze) \ast\frac{fy}{\gamma mo}$

MD=1.12$\ast(\frac{1\times t^{2}}{6})\ast \frac{250}{1.1}$.....(4)

Equate equation 3&4

216.43$\times10^{3}=1.12+(\frac{1\times t^{2}}{7}\ast \frac{250}{1.1}$

t=71.23

t=72mm

But central portion has Bm in two direction t=$\frac{72}{2}$=36mm

Provide t=36mm

Provide base plate =460$\times750\times36$

Thickness of plate

Connection ( Bolted connection )

1) vdsb=$\frac{fub\times Anb\times nn}{\sqrt{3}\ast \gamma mb}$ assume 30mm dis of bolt

=>$\frac{400\times (0.78\times\frac{pi}{4}\times30^{2})\ast1}{\sqrt{3}\ast1.25}$

Vas’s=101.86$\times10^{3}$

Vdpb=2$\times kb\times d\times t \times fu$

=2$\times 0.5\times 30\times 15\times 410$

Vdpb=184.5$\times 10^{3}N$

Bolt value b=101.86 kN

No of bolts =$\frac{load/2}{Bolts / value}$=50x load directly vat 50% by connection

$\frac{4.105\times10^{3}/2}{101.86\times10^{3}}$ =20.15

Provide 24 bolts

No of bolts required to connect gusset with gusset angle will be same

Provide 24 bolts 30mm $\phi$ on each flange in two rows

Design of Anchor bolts

Holding down vbase plate by 6 nos30 mm$\phi$ at bolt of length 300 mm ( length x concrete Aedertal