written 5.8 years ago by |
or translation free fy=250mpa & grade of steel 410
Given:-
TSHB 3000 A= 7485 mm$^{2}$ bf=250 tf=10.6 tw=7.6
Izz=Ixx=12545.2$\times10^{4}mm^{4}$
Iyy=2293.6 $\times10^{4}mm^{4}$
$\frac{KL}{ryy}$=compund section
$\frac{KL}{\gamma xx}$= compund section
$\gamma xx=\sqrt{\frac{Ixx}{A}}$
$\gamma yy=\sqrt{\frac{Iyy}{A}}$
A=7458+2(Area of plate)
=7485+2(350$\times$20)
A=24485mm$^{2}$
Ixx of compound section
Ixx=Ixx1+Ixx2
=(1.2545.2$\times 10^{4})+(\frac{350\times20^{3}}{12}+(350\times20)(160)^{2})$
Ixx=484.32$\times10^{6}mm^{4}$
Iyy=Iyy1+Iyy2
=2193.6$\times10^{4}+2(\frac{20\times350^{3}}{12}+(20\times350)\times0)$
Iyy=164.85$\times10^{6}mm^{4}$
$\gamma xx=\sqrt{\frac{484385\times10^{6}}{21485}}$ rxx 150.29mm
$\gamma yy$=87.5ymm
leff=10.000mm
$\gamma=\frac{kL}{\gamma xx}=\frac{2\times50.00}{150.29}=66.53$
$\frac{h}{bf}=\frac{3000}{250}=1.36\gt 1.2$
buckling about z axis class a
thickness of flange 10.6$\lt 40$
buckling about y axis class b
KL/$\gamma $xx $\ \ \ \ \ $fcd
60 $ \ \ \ \ \ \ \ \ \ \ $ 195
66.53 $ \ \ \ \ \ \ $ fcd
70 $ \ \ \ \ \ \ \ \ \ \ \ 18^{2}$
$\frac{70-60}{70-66.53}=\frac{182-195}{182-fcd}$
fcd=186.5N/mm$^{2}$
Pd=Ae$\times$fcd
Pd=21485$\times186.5$
Pd=4005.1 KN
$\frac{KL}{\gamma yy}=\frac{10,000}{87.6}=$114.15
KL/$\gamma yy \ \ \ \ fcd$
110 $ \ \ \ \ \ \ \ $ 104
114.15 $ \ \ \ $ fcd
120 $ \ \ \ \ \ \ \ \ \ $ 91.7
$\frac{120-110}{120-114.15}=\frac{91.7-104}{91.7-fcd}$
fcd=98.8N/mm$^{2}$
Pd=Ae$\times$ fcd
=21485$\times$98.8
PD=2124.5KN
design comp strenght of column=2124.5KN