A gaseous fuel contains $H_2$=50%, $CH_4$= 30%, $N_2$=2%, CO =7%,$C_2 H_4$ =3%, $C_2 H

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A gaseous fuel contains $H_2$=50%, $CH_4$= 30%, $N_2$=2%, CO =7%,$C_2 H_4$ =3%, $C_2 H_6$ = 5% and water vapour = 3%

written 5.9 years ago by

vibhavarikulkarni • 510

modified 4.7 years ago by

sanketshingote • 100

calculate weight and volume of air required for $2m^3$ of the gas

advanced engineering chemistry

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written 5.8 years ago by

vibhavarikulkarni • 510

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$H_2 + \frac{1}{2} O_2 H_2O$ = $0.25 m^3$

1vol 0.5 vol

$CH_4 +2O_2 CO_2+2H_2O = 0.6 m^3$

$CO+\frac{1}{2} O_2 CO_2 = 0.035 m^3$

$C_2H_4 +3O_2 2CO_2 +2H_2O = 0.09 m^3$

$C_2H_6+3O_2 2CO_2 + O_2 = 0.15 m^3$

$= 0.25 m^3 + 0.035m^3 + 0.6 m^3 + 0.09 m^3 + 0.175 m^3$

Amount of oxygen required = $1.15 m^3$

Volume of air required = $1.15 \times 2 = 2.30 m^3$

$2.30 m^3$ of air will weigh = $ \frac{2.30}{22.4} \times 28.949 = 2.97 Kg$

$\therefore$ Wt of air required = 2.97 Kg

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