A sample of coal has the following composites: C = 70%, O = 23%, H = 5%, S = 1.5%, N = 0.4%, Ash = 0.1%, calculate the G.C.V. of this fuel.

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written 6.2 years ago by

vibhavarikulkarni • 520

modified 5.0 years ago by

sanketshingote • 100

advanced engineering chemistry

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1 Answer

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written 6.1 years ago by

vibhavarikulkarni • 520

modified 6.1 years ago by

yashbeer ★ 11k

Solutions:

$\begin{align} HCV &= \frac{1}{100} [8080 C+34500(H- \frac{O}{8}) +2240 S] \\ &= \frac{1}{100} [8080 + 70+34500(10-23/8) +2240 \times 1.5] \\ &= \frac{1}{100} [565600 + 34500 (10-1) \times 3360] \\ &= \frac{1}{100} [642272.5] \\ &= 6422.725kcal/kg \\ \end{align}$

Answer:

$HCV/GCV=6422.725 \space kcal/kg$

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