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A sample of coal has the following composites: C = 70%, O = 23%, H = 5%, S = 1.5%, N = 0.4%, Ash = 0.1%, calculate the G.C.V. of this fuel.
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Solutions:

HCV=1100[8080C+34500(HO8)+2240S]=1100[8080+70+34500(1023/8)+2240×1.5]=1100[565600+34500(101)×3360]=1100[642272.5]=6422.725kcal/kg

Answer:

HCV/GCV=6422.725 kcal/kg

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