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A sample of coal has the following composites: C = 70%, O = 23%, H = 5%, S = 1.5%, N = 0.4%, Ash = 0.1%, calculate the G.C.V. of this fuel.
1 Answer
written 6.1 years ago by | modified 6.1 years ago by |
Solutions:
HCV=1100[8080C+34500(H−O8)+2240S]=1100[8080+70+34500(10−23/8)+2240×1.5]=1100[565600+34500(10−1)×3360]=1100[642272.5]=6422.725kcal/kg
Answer:
HCV/GCV=6422.725 kcal/kg