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Calculate the higher and lower calorific values of coal sample containing 84% carbon, 1,5% sulphur, 0.6 nitrogen, 8.4% hydrogen and 5.5% oxygen
written 6.2 years ago by gravatar for vibhavarikulkarni vibhavarikulkarni • 520 modified 5.0 years ago by gravatar for sanketshingote sanketshingote • 100
advanced engineering chemistry
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written 6.1 years ago by gravatar for vibhavarikulkarni vibhavarikulkarni • 520 modified 6.1 years ago by gravatar for yashbeer yashbeer ★ 11k

Solution is as follows:

$\begin{aligned} HCV &= \frac{1}{100} \bigg[8080 C+34500(H-O/8) +2240 S \bigg] \\ &= \frac{1}{100} \bigg[8080 \times 84+34500(8.4-5.5/8) + 2240 \times 1.5 \bigg] \\ &= \frac{1}{100} \bigg[678720 + 34500 (7.71) \times 2240 \times 1.5 \bigg] \\ &= \frac{1}{100} \bigg[678720 + 265995+ 3360 \bigg] \\ &= \frac{1}{100} [948075] \\ &= …

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