Calculate weight of air needed for complete combustion of 2kg of coal containing C =70%, H= 10%, O=10%, N=5% and remaining ash

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written 5.9 years ago by

vibhavarikulkarni • 510

modified 4.7 years ago by

sanketshingote • 100

advanced engineering chemistry

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1 Answer

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written 5.8 years ago by

vibhavarikulkarni • 510

modified 5.8 years ago by

yashbeer ★ 11k

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$\begin{aligned} \text{Wt. of oxygen} &= \text{wt. of oxygen needed } – \text{wt. of oxygen present} \\ &= 2.66 – 0.1 \\ &= 2.56 kg \\ \end{aligned}$

$\text{Wt. of air required for complete combustion}$

$\begin{aligned} &= \text{[Air contains 23% } O_2 \text{ by weight ]} \\ 2.56 \times 100 / 23 &= 11.13 \text{kg per 1 kg of coal} \\ \text{Air required for 2 kg of coal} &= 11.13 \times 52 \\ &= 22.26 kg \end{aligned}$

Answer: Weight of air required = 22.26 kg

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