0
3.0kviews
A coal sample contains C = 70%, O= 5%, H = 23%, N = 0.4%, ash = 0.1%. calculate GCV and NCV of the fuel.
1 Answer
written 6.1 years ago by |
Solutions:
HCV=1/100[8080C+34500(H−O/8)+2240S]=1/100[8080×70+34500(23−5/8)+2240×0]=1/100[565600+34500(2.37)×2240]=1/100[565600+81.765+2240]=1/100[567921.765]=5679.21 kcal/kg
LCV=[HCV−9×H/100H×587]=[5679.21−9×23/100×587]=4464.12kcal/kg
Answer:
HCV/GCV = 5679.21 kcal/kg
LCV/NCV = 4464.12 kcal/kg