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A coal sample contains C = 70%, O= 5%, H = 23%, N = 0.4%, ash = 0.1%. calculate GCV and NCV of the fuel.
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Solutions:

HCV=1/100[8080C+34500(HO/8)+2240S]=1/100[8080×70+34500(235/8)+2240×0]=1/100[565600+34500(2.37)×2240]=1/100[565600+81.765+2240]=1/100[567921.765]=5679.21 kcal/kg

$\begin{aligned} LCV &= [HCV- 9 \times H/100 …

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