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If the basic runway length for an airport situated at an elevation of 180 meter is 800 meter. Find the actual runway length required if mean of average daily temperature and

mean of maximum daily temperature is obtained as 36o c and 42o C respectively . Assume the effective gradient of 2% on the runway.

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  • Basic Runway length =800 m.
    • Elevation correction =7100×800×180300 =33.6 m
    • Correction Runway length after Elevation correction =833.6 m
    • ART (Airport Ref. Temp)=Ta+(TmTa3) =36+(42363)=38C
    • Stand. Atm Temp. =15(0.0065×180)=13.83C
    • Rise in temp =3813.83=24.17C
    • $\begin{aligned} \text { Temp.Correction } &=\frac{1}{100} …

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