If the basic runway length for an airport situated at an elevation of 180 meter is 800 meter. Find the actual runway length required if mean of average daily temperature and

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written 6.2 years ago by

teamques10 ★ 69k

modified 3.0 years ago by

sagarkolekar ★ 11k

mean of maximum daily temperature is obtained as $36^o$ c and $42^o$ C respectively . Assume the effective gradient of 2% on the runway.

transportation engineering

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written 3.0 years ago by

Chandan15 • 300

• modified 3.0 years ago

Basic Runway length =800 m.
- Elevation correction $=\frac{7}{100} \times 800 \times \frac{180}{300}$ $=33.6 \mathrm{~m}$
- Correction Runway length after Elevation correction $=833.6 \mathrm{~m}$
- $A R T$ (Airport Ref. $\operatorname{Temp} ) =T_{a}+\left(\frac{T_{m}-T_{a}}{3}\right)$ $=36+\left(\frac{42-36}{3}\right)=38^{\circ} \mathrm{C}$
- Stand. Atm Temp. $=15^{\circ}-(0.0065 \times 180)=13.83^{\circ} \mathrm{C}$
- Rise in temp $=38-13.83=24.17^{\circ} \mathrm{C}$
- $\begin{aligned} \text { Temp.Correction } &=\frac{1}{100} …

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Please, improve the formatting.

3.0 years ago by prakhar1144 ★ 5.0k

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