Locate the shear centre for thin walled channel section as shown in figure. Assume the uniform section as 10mm. Cross sectional dimension are in mm.

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written 6.2 years ago by

ashishgoklani • 180

modified 3.0 years ago by

Chandan15 • 300

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Subject: Structural Analysis 1

Topic: Shear Centre

Difficulty: High

structural analysis

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1 Answer

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written 3.0 years ago by

Chandan15 • 300

• modified 3.0 years ago

Using Relation, $e=\frac{b^{2} h^{2} t}{4 I_{A O S}}$ $I_{AOS}=\left(\frac{1 00 \times 300^3}{12}\right)-\left(\frac{90 \times 280^3}{12}\right).$ $I_{\text {AOS }}=60.36 \times 10^{6} \mathrm{~mm}^{4}$ $Shear Centre, e=\frac{95^{2} \times 290^{2} \times 10}{4 \times 60.36 \times 10^{6}}=31.436 \mathrm{~mm}$

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