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An AM signal is produced by modulating a carrier signal with peak voltage of 10V and Frequency of 100kHz by an information signal with max modulating frequency of 5KHz and max amplitude 4V. Determine

a.) Frequency limit for lower and upper side band

b.) Bandwidth of AM

c.) Total power of the modulated wave if the load resistance Rl = 10 ohms

d.) Draw the power spectrum.

e.) Calculate the total transmitted current.

Mumbai University > Electronics > Sem 4 > Priniciples of Communication Engineering

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Given :

fc = 100KHz

fm(max) = 5KHz

a) Frequency limits for upper and lower sideband

fupper=fc+fm(max) = 105 kHz

flower=fcfm(max) = 95 kHz

b) Bandwidth of AM

Bandwidth = fupperflower = 105kHz - 95 kHz = 10kHz.

OR

Bandwidth = 2fm(max) = 2 (5 kHz) = 10 kHz

c) Total Power

Pc=V2c2R=1022(10)=5W

PLSB=m2Pc4=(1)2×54=125W

PUSB=m2Pc4=(1)2×54=125w

Pt=Pc+PLSB+PUSB

= 5 + 1.25 + 1.25 = 7.5

d) Power spectrum

enter image description here

e) Current Transmitted

Pt=Pc(1+m22)

But, P=I2R

I2tR=PC(1+m22)

= 5 (1+12)

I2t=7.510

It=7.510

It = 0.866 A

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