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An electron is accelerated through a potential difference of 5 kV and enters a uniform magnetic field of 0.02 Wb/m2 acting normal to the direction of electron motion.
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v=2qVm=2×1.6×1019×50009.1×1031=4193×104 r=mvqB=9.1×1031×4193×1041.6×1019×0.02=0.0119m

Radius of path =0.0119 m

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