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If ˉA=x2zˉi2y2z2ˉj+xy2zˉk. Find A at point (1,-1,1)
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Solution:

ˉA=x2zˉi2y2z2ˉj+xy2zˉk

The divergence of ˉA is given by

.ˉA=Axx+Ayy+Azz

Axx=2xzAyy=4yz2Azz=xy2

Then, .ˉA=2xz4yz2+xy2

At (1, -1, 1), .ˉA=2(1)(1)4(1)(1)2+(1)(1)2=7

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