Assume following processes arrive for execution at the indiacted and length of cpu burst time in ms.

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written 5.9 years ago by

0309rishika • 520

modified 3.1 years ago by

sagarkolekar ★ 11k

Process	Burst Time	Arrival time	Priority
P1	10	0	5
P2	6	0	2
P3	7	1	4
P4	4	1	1
P5	5	2	3

Find AWT, ATAT for FCFS, SJF (mon - preemptive) and round robin (Quantum -3ms)

operating systems

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written 3.1 years ago by

apsareena • 670

First come First Serve:

Gant chart:

  A     B     C     D     E
0   10    16    23    27    32

Job	Arrival Time	Burst Time	Finish Time	Turnaround Time	Waiting Time
A	0	10	10	10	0
B	0	6	16	16	10
C	1	7	23	22	15
D	1	4	27	26	22
E	2	5	32	30	25
Average				104 / 5 = 20.8	72 / 5 = 14.4

Shortest Job First (non-premptive)

Gant chart:

    B    D    E    C    A
0    6    10    15    22    32

Job	Arrival Time	Burst Time	Finish Time	Turnaround Time	Waiting Time
A	0	10	32	32	22
B	0	6	6	6	0
C	1	7	22	21	14
D	1	4	10	9	5
E	2	5	15	13	8
Average				81 / 5 = 16.2	49 / 5 = 9.8

Round Robin time quantum = 3

Gant chart:

   A    B    C    D    E     A      B    C     D     E     A     C     A
0    3    6    9    12    15    18    21    24    25    27    30    31    32

Job	Arrival Time	Burst Time	Finish Time	Turnaround Time	Waiting Time
A	0	10	32	32	22
B	0	6	21	21	15
C	1	7	31	30	23
D	1	4	25	24	20
E	2	5	27	25	20
Average				132 / 5 = 26.4	100 / 5 = 20

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