Derive the equation of contrast stretching transformation function as given in figure below.

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written 8.9 years ago by

teamques10 ★ 69k

• modified 4.9 years ago

Apply the contrast stretching transformation function on the input image F and obtain the output image R.

enter image description here

image processing

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written 8.9 years ago by

teamques10 ★ 69k

• modified 8.9 years ago

Step 1: Derivation of Transform:

enter image description here

$S = \begin{bmatrix} αr & 0≤r≤a \ S_1+β(r-a) & a<r≤b \="" s_2+γ(r-b)="" &="" b<r≤l-1="" \="" \end{bmatrix}=""$ <="" p="">

When a = 8, b = 12, L – 1 = 15

S1 = 4, S2 = 8

We get, α = 0.5, β = 1, γ …

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