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consider analog i/p which has the 8 bit digital equivalent as 11010100. The conversion seqn that will take place obtain the required binary o/p is as follwos
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written 5.7 years ago by |
From the table we can see that
For $V_{A}\geq V_{D} $ the comparator o/p becomes high and for $v_{A}\lt v_{D} $ the comprator o/p is low