Crystal frequency= 11.0592 MHz

$ I/P clock= \frac {1}{2} \times ( crystal frequency) = \frac {1}{2} \times 11.0592 MHz = 921.6 KHz$

Tin =1.085μsec

For5 kHz square wave

Fout = 5KHz

Tout = $ \frac{1}{5 \times 10^3} = 200 \mu sec$

Tout =200μsec

Consider half of it=Tout = 100μ sec

$ N = \frac{Tout}{Tin} = \frac{100\mu}{1.085\mu} = 100\mu sec$

65536-92= (65444)D =FFA5 H

Program:

#include< reg51.h>

void delay(void);

sbit p=P3^5;

void main (void)

{

    while (1)

    {

        p=~p;

        delay();

    }

}

void delay()

{

    TMOD=0X01; $ \ \ \ \ \ \ \ \ \ \ $//set timer 0 in mode 1 i.e. 16 bit number

    TL0=0XA5H; $ \ \ \ \ \ \ \ \ \ \ $//load TL register with LSB of count

    TH0=0XFFH ; $ \ \ \ \ \ \ \ \ \ \ $//Load TH register with MSB of count

    TR0 =1 ; $ \ \ \ \ \ \ \ \ \ \ $//Start timer 0

    While(TF0= = 0); $ \ \ \ \ \ \ \ \ \ \ $ //wait until timer rolls over

    TR0=0; $ \ \ \ \ \ \ \ \ \ \ $//Stop timer 0

    TF0=0; $ \ \ \ \ \ \ \ \ \ \ $//Clear timer flag 0

}