written 8.6 years ago by |
The transmitter (modulator) of a DEPSK system is identical to the DPSK transmitter.
The differential phase shift keying (DPSK) is a modulation of BPSK.
Fig shows the block diagram of DPSK generator and the relevant waveforms.
Operation:
d (t) represents the data stream which is to be transmitted .It is applied to one input of an EX-OR logic gate.
The EX-OR gate output “b (t)” is delayed by one bit period Tb and applied to the other input of the EX-OR gate. The delayed output is represented by “$b(t- T_b )$”
Depending on the values of “”d (t)” and “$b(t- T_b )$” ,the EX-OR gate produces the output sequence “b (t)” .The waveforms for DPSK generator have been drawn by arbitrarily that in the first interval b (0)=0.
Output of EX-OR gate is then applied to a bipolar NRZ level shifter which converts “b(t)” to a bipolar level signal b’(t) as shown in the fig.
This bipolar NRZ signal b’(t) is then multiplied with the carrier signal to produce the DPSK signal. The DPSK output signal is mathematically expressed as:
$V_{DPSK} (t) = b’(t) * \sqrt{2 P_s} cosω_C t$
So when b(t) =1 , b’(t) =1 hence
$V_{DPSK} (t) = $b'(t)$ * \sqrt{2 P_s} cosω_C t$
That means no phase shift has been introduced.
Bt when b(t) =0, b’(t)= -1 hence
Thus 180 degree phase shift is introduced to represent b(t) =0
The block diagram of DEPSK receiver is shown below. It shows that the signal b (t) is recovered from the received signal, using the synchronous demodulation technique. This is same as the BPSK detection. Once the signal b (t) is recovered, it is applied to one input of an EX-OR gate.
The signal b(t) is also applied to a time delay circuit and the delayed signal $b(t- T_b )$ is applied to the other input of the EX-OR gate as shown below
If b(t)= $b(t- T_b )$ then output of the EX-OR gate will be 0
d (t) =0 ………if b$ (t) = b(t- T_b )$
And if b(t) = $b(t- T_b )$ then output of the EX-OR gate will be 1
d (t) =1 ……… b(t) = b$(t- T_b )$