written 5.9 years ago by | • modified 5.6 years ago |
Subject :- VLSI Design
Topic :- MOSFET Inverters
Difficulty - Medium
written 5.9 years ago by | • modified 5.6 years ago |
Subject :- VLSI Design
Topic :- MOSFET Inverters
Difficulty - Medium
written 5.6 years ago by |
To design Noise Margins
$NM_H$ = VOH – VIH
$NM_L$ = VIL – VOL
Step 1: Find VIL
$I_L$ = $I_D$
When Vin = VIL; nMOS is in saturation region and pMOS is in linear region
Differentiate w.r.t. Vin and substitute
Step 2: Find VIH
When Vin = VIH ; inverter is in D region and nMOS is in linear region and pMOS is in saturation region.
Differentiate w.r.t. Vin and substitute
Step 3: Find VOH
When Vin = 0 V; Vout = VOH i.e. Vgs,n < VT,n
nMOS is in cutoff region and pMOS is conducting i.e. it is in linear region.
Vout = VOH = VDD
Step 4: Find VOL
when Vin = VDD
nMOS is conducting and in linear region and pMOS is in cutoff region.
Therefore $I_L$ = $I_D$
Since $I_L$ = 0
Vout = VOL = 0V