Calculate the cut off wavelength, the guide wavelength, phase velocity and the characterestic wave impedance for TE110 mode.

emphasized textCalculating the free space wavelenth gives

$\lambda = \frac{v_c}{f} = \frac{3\times10^{10}}{9\times10^{10}}= 3.33 cm$

a. The cutoff wavelenth will be

$\lambda _0 = \frac{2a}{m} = \frac{2 \times 4.5}{1} = 9 cm Calculating p, for convenience, gives$ p = \sqrt {1-(\frac{\lambda}{\lambda _0})^2} = \sqrt {1-(\frac{3.33}{9})^2} = \sqrt …