Calculate critical angle of incidence between two substances with different refractive indices n1 = 1.5 and n2 = 1.46.

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written 6.3 years ago by

teamques10 ★ 69k

• modified 5.0 years ago

advanced communication system

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written 6.2 years ago by

teamques10 ★ 69k

• modified 6.2 years ago

Given :

$n_1$ = 1.5

$n_2$ = 1.46

Formulae :

$\theta_c = sin^{-1} (\frac{n_2}{n_1})$

$\theta_c = sin^{-1} (\frac{1.46}{1.5})$

$\theta_c = {76.74}^o$

$\theta_c$ = 1.339 radians

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