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A rectangular waveguide is 5 cm x 2.5 cm. Calculate cutoff freq. of dominant mode.

written 5.9 years ago by teamques10 ★ 68k

•   modified 4.7 years ago

advanced communication system

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written 5.8 years ago by teamques10 ★ 68k

•   modified 5.8 years ago

The dominant mode of a rectangular waveguide is the TE1,0 mode, with m=1 & n=0

$F_c$ = $1.5*10^{8}{\sqrt{({\frac{m}{a})^2}+ ({\frac{n}{b}})^2}}$

$F_c$ = $1.5*10^{8}{\sqrt{({\frac{1}{0.050})^2}+ ({\frac{0}{0.025}})^2}}$

$F_c$ = 3 GHz

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