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The velocity potential function for two dimensional flow is = x(2y-1) determine: (i) velocity, and (ii) stream function
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i)Velocity potential function for two dimensional flow(∅)=x(2y-1)

Velocity, u=x

Therefore, u= ((x(2y1))x

= (2y-1)+(x×(2(0)-0))

=(2y-1) (ans)

Velocity, v=()y

Therefore, v=((x(2y1)))y

= x×(2-1)

= x. (ans)

ii) Stream function ψ=f(x,y) In velocity we can write u=ψy , v=ψx ∴ (2y-1)= ψy (2y-1) ∂y= ∂ψ Now integrating above equation (2y1)y=ψ 2y22+y+C(x)=ψ

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Weight of stone in air=245N

Mass of stone =2459.81=24.97Kg

Volume=mass(density of water)=24.971000=.02497m3 ….(ans)

ρfluid=s×1000

Mass of stone in water= 1689.81=17.25kg

ρfluid=massvolume=17.25.02497=685.823

Specific gravity=ρfluid1000=685.8231000=.6858 ……..(ans)

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