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The velocity potential function for two dimensional flow is = x(2y-1) determine: (i) velocity, and (ii) stream function
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written 6.3 years ago by | • modified 6.3 years ago |
i)Velocity potential function for two dimensional flow(∅)=x(2y-1)
Velocity, u=∂∅∂x
Therefore, u= (∂(x(2y−1))∂x
= (2y-1)+(x×(2(0)-0))
=(2y-1) (ans)
Velocity, v=(∂∅)∂y
Therefore, v=(∂(x(2y−1)))∂y
= x×(2-1)
= x. (ans)
ii) Stream function ψ=f(x,y) In velocity we can write u=∂ψ∂y , v=−∂ψ∂x ∴ (2y-1)= ∂ψ∂y (2y-1) ∂y= ∂ψ Now integrating above equation ∫(2y−1)∂y=∫∂ψ 2y22+y+C(x)=ψ …
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written 6.3 years ago by | • modified 6.3 years ago |
Weight of stone in air=245N
Mass of stone =2459.81=24.97Kg
Volume=mass(density of water)=24.971000=.02497m3 ….(ans)
ρfluid=s×1000
Mass of stone in water= 1689.81=17.25kg
ρfluid=massvolume=17.25.02497=685.823
Specific gravity=ρfluid1000=685.8231000=.6858 ……..(ans)
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