written 6.3 years ago by
teamques10
★ 69k
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modified 6.3 years ago
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Where f = friction factor
L= length of duct in meter
v = velocity of air in duct in m/sec
D= diameter of duct in meter
Discharge through duct is given by, Q= A.v …….(2)
Where A = cross sectional area of duct
Expression for the equivalent diameter of a circular duct corresponding to a rectangular duct when the quantity of air passing through both ducts is same
Substituting equation (2) in equation (1),
hfL=(f(Q/A)2)2gD
D5=64(a,b)22π2(a+b)
D=1.265a3b3a+b1/5
ii.Expression for the equivalent diameter of a circular duct corresponding to a rectangular duct when the velocity of air flowing through both ducts is same
We can write velocity from equation (1) as

a,b2(a+b)=π4D2π.D
D=2aba+b