0
7.2kviews
Derive expression equivalent diameter of circular duct corresponding to rectangular duct of sides for same pressure loss per unit length when

i. The quantity of air passing through both ducts is same and

ii. The velocity of air flowing through both ducts is same

The friction factor remains same for both ducts

Subject:- Refrigeration and Air Conditioning

Topic:- Duct Design, Controls & Applications

Difficulty:- Medium

1 Answer
1
509views

enter image description here

Where f = friction factor

L= length of duct in meter

v = velocity of air in duct in m/sec

D= diameter of duct in meter

Discharge through duct is given by, Q= A.v …….(2)

Where A = cross sectional area of duct

Expression for the equivalent diameter of a circular duct corresponding to a rectangular duct when the quantity of air passing through both ducts is same

Substituting equation (2) in equation (1),

$\frac{h_f}{L}=\frac{(f(Q/A)^2)}{2gD}$

enter image description here

$D^{5}=\frac{64(a,b)^{2}}{2\pi^{2}(a+b)}$

D=1.265$\frac{a^{3}b^{3}}{a+b}^{1/5}$

ii.Expression for the equivalent diameter of a circular duct corresponding to a rectangular duct when the velocity of air flowing through both ducts is same

We can write velocity from equation (1) as

enter image description here

$\frac{a,b}{2(a+b)}$=$\frac{\frac{\pi}{4}D^{2}}{\pi.D}$

$D=\frac{2ab}{a+b}$

Please log in to add an answer.