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An element in a stressed body is subjected to normal stresses on mutually perpendicular directions as shown in fig.

An element in a stressed body is subjected to normal stresses on mutually perpendicular directions as shown in fig. Determine the normal tangential and resultant stresses on plane P-P inclined as shown. Either use analytical method or graphical method.

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From above figure, we get,

P1=100 Mpa (tensile)

P2=60 Mpa (tensile)

θ=30°

A] Normal stress on P – P Plane.

σn=P1+P22+(p1p22) cos 2 θ

$= \frac{100 + 60}{2} + (\frac{100 – …

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