The following observations were made in a standard Practor's Test. Draw the dry density unit weight versus water content graph

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written 6.0 years ago by

teamques10 ★ 67k

• modified 6.0 years ago

Volume of practor mould = 945 c.c

∴ γbulk = (Mass of soil) + (Volume of soil) = 945 cc | gm/c.c

∴ γdry = {( γbulk)/(1+ω)}

w = % with content

= (G .γω)/(1+ ωG) (For saturate sample or for zero air void line)

Trail Number	1	2	3	4	5
Mass of wet soil	1673	1814	1928	1985	1947
γbulk X k (gm/c.c)	1.77	1.97	2.04	2.1	2.06
ω = water content	9.7	11.6	13.3	16.2	18.7
γdry = {( γbulk)/(1+ω)}	1.613	1.72	1.8005	1.8076	1.735
Co–ordinate of zero air void line	2.099	2.017	1.949	1.843	1.76

γ Co–ordinate of zero void line

γdry = (G .γω)/(1+ ωG)

= (2.7 X 9.81)/(1+(0.097)X (2.7)) = 2.099 { γ = 0.981, (G = 2.7)} (ω = 9.7%)

= (2.7 X 9.81)/(1+(0.116)X (2.7)) = 2.017 ( ω= 11.6%)

= (2.7 X 9.81)/(1+(0.133)X (2.7)) = 1.949 ( ω= 13.3%)

= (2.7 X 9.81)/(1+(0.162)X (2.7)) = 1.843 ( ω= 16.2%)

= (2.7 X 9.81)/(1+(0.187)X (2.7)) = 1.76 ( ω= 18.7%)

Calculated :

OMC = 16.2 %

MDD = 1.8076

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