Locate core (i.e kernel) of the solid rectangular section of width 400 mm and depth 600 mm.

Welcome back.

and 5 others joined a min ago.

5.8kviews

written 6.4 years ago by

tarashankarsharma • 550

modified 5.4 years ago by

sanketshingote • 100

strength of materials

ADD COMMENT EDIT

2 Answers

226views

written 5.5 years ago by

teamques10 ★ 69k

• modified 5.4 years ago

enter image description here

[1] Area of section = $400 \times 600 = 24 \times 10^4 \ mm^2$

[2] Section modulus about XX – axis = $\frac{bd^2}{6} = \frac{400 \times 600^2}{6} = 24 \times 10^6 \ mm^3$

[3] Section modulus about YY – axis = $\frac{db^2}{6} = \frac{600 \times 400^2}{6} = 16 \times …

and 4 others joined a min ago.

ADD COMMENT EDIT

266views

written 6.4 years ago by

tarashankarsharma • 550

and 2 others joined a min ago.

ADD COMMENT EDIT

Community

Content

Company