The maximum torque is 20% more than the average torque. The permissible shear stress is 90 N/mm^2 and twist is 1 degree per 3 m length. Calculate the power transmitted if G=84000 N/mm^2.

Data: do = 120 mm, di = 100 mm

N = 200 rpm

$T_{max} = \frac{120}{100} \ T_{avg}$

$\zeta = 90 \ N/mm^2$ $\theta = 1°$ l = 3000 mm

G = 84000 $N/mm^2$

Solution:

$J_p = \frac{\pi}{32} (120^4 – 100^4)$

$Jp = 10.54 \times 10^6 mm^4$

[1] $\frac{T_{max}}{Jp} …