Determine the maximum torque that can be applied safely to a solid shaft of diameter 260 mm.

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written 6.5 years ago by

tarashankarsharma • 550

modified 5.4 years ago by

sanketshingote • 100

The permissible angle of twist=1.30 in length of 6 m and the shear stress is not exceed 61 MPa. Take Modulus of Rigidity G=90 MPa.

strength of materials

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written 6.5 years ago by

tarashankarsharma • 550

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written 5.5 years ago by

teamques10 ★ 69k

Data: Diameter (d) = 260 mm.

$r = \frac{260}{2} = 130 \ mm$

Angle of twist $(\theta) = 1.3° = (1.3 \times \frac{\pi}{180})$ (radians)

Length (L) = 6m = 6000 mm

Shear stress $\zeta = 61 \ Mpa$ and G = 90 Mpa

$T_{max} = ?$

1] Torque from strength: …

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