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A hollow rectangular section 250 mm x 500 mm externally and has uniform thickness 50 mm, if the shear force at the section is 50kN. Find the maximum shear stress.

written 6.4 years ago by tarashankarsharma • 550

modified 5.4 years ago by sanketshingote • 100

strength of materials

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written 6.4 years ago by teamques10 ★ 69k

•   modified 6.4 years ago

$I_{NA}=\frac{250*500^3}{12}-\frac{150*400^3}{12}$

$I_{NA}=1.8041*10^9 {mm}^4$

$q_{NA}=\frac{50*10^3(250*250*125-150*200*100)}{1.804*10^9*100}$

$q_{NA}=1.334 MPa$

$q_{11}=q_{22}=\frac{50*10^3(250*50*225)}{1.804*10^9*b}$

= 0.312MPa when b=200mm

= 0.779 MPa when b=100mm

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