A hollow rectangular section 250 mm x 500 mm externally and has uniform thickness 50 mm, if the shear force at the section is 50kN. Find the maximum shear stress.

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written 6.1 years ago by

tarashankarsharma • 550

modified 5.0 years ago by

sanketshingote • 100

strength of materials

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1 Answer

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written 6.0 years ago by

teamques10 ★ 68k

• modified 6.0 years ago

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$I_{NA}=\frac{250*500^3}{12}-\frac{150*400^3}{12}$

$I_{NA}=1.8041*10^9 {mm}^4$

$q_{NA}=\frac{50*10^3(250*250*125-150*200*100)}{1.804*10^9*100}$

$q_{NA}=1.334 MPa$

$q_{11}=q_{22}=\frac{50*10^3(250*50*225)}{1.804*10^9*b}$

= 0.312MPa when b=200mm

= 0.779 MPa when b=100mm

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