The wind intensity is $1.3 KN/m^2$ on projected area and specific weight of the measure is $22 KN/m^2$. Calculate the maximum and minimum stresses of the base of the chimney.

$\textit{Wind pressure} = 1.3\hspace{0.05cm}KN/m^2\\ W = 22\hspace{0.05cm}KN/m^2\\ y = \frac{2.5}{2} = 1250\hspace{0.05cm}mm$

(i) $\textit{Projected Area} = 24\hspace{0.05cm}\times\hspace{0.05cm}2.5\\ \hspace{02cm} = 60\hspace{0.05cm}m^2$

(ii) $\textit{Wind force} (P) = \textit{Wind pressure X projected area}\\ \hspace{02cm} = 1.3\hspace{0.05cm}\times\hspace{0.05cm}60\\ \hspace{02cm} = 78\hspace{0.05cm}KN = 78\hspace{0.05cm}\times\hspace{0.05cm}10^3\hspace{0.05cm}N$

(iii)$\textit{self weight} = W\hspace{0.05cm}\times\hspace{0.05cm}Volume\\ \hspace{02cm} = W\hspace{0.05cm}\times\hspace{0.05cm}A\hspace{0.05cm}\times\hspace{0.05cm}L\\ \hspace{02cm} = 22\hspace{0.05cm}\times\hspace{0.05cm}[(1.25\hspace{0.05cm}\times\hspace{0.05cm}1.25) - (2.5\hspace{0.05cm}\times\hspace{0.05cm}2.5)]\hspace{0.05cm}\times\hspace{0.05cm}24\\ …