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A rectangular beam section 300mm wide and 500mm deep is simply supported over a span of 4m.It carries full span UDL of 10 KN/m.Find max. bending stress induced in the section and draw the distribution
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Given

L=4m,UDL=10KN/m=10×103N/m

To Findσb=?

Solution

enter image description here

ER=MI=σby

Mmax=WL28=10×103×428=20000Nm=20000×103Nmm

y=d2=5002=250mm

I=bd312=300×500312=31.25×108mm4

$\frac{M}{I} = \frac{\sigma_b}{y}\\ \frac{20000\hspace{0.05cm}\times\hspace{0.05cm}10^3}{31.25\hspace{0.05cm}\times\hspace{0.05cm}10^8} = …

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