0
4.8kviews
A steel rod is placed between two copper bar, each having same area and length. As a steel bar at 15 deg Cel. At this stage they are connected together when the temperature is raised to 315 deg Cel.

The length of the bar is increased by 1.5mm. Determine the original length and find the stresses in the bar. Take ES=2.1X105MPa;αS=12X106/°C;EC=1X105MPa;αS=17.5X106/°C

1 Answer
0
701views

enter image description here

For parallel combination

2×Pcu=Pst2×σcAc=σsAs2×σc×1=σs×1σs=2σc

(αLt)cu+(αLt)st(PLAE)cu(PLAE)st=1.5(17.5×106×L×300)+(12×106×L×300)(σc×L1×105)cu(2σcu×L2.1×105)st=1.5ϵcu+ϵst=(αcuαst).t(σE)cu+(σE)st=(αcuαst)t0.5σst1×105+σst2.1×105=(17.5×10612×106)×300σst=169.024N/mm2σcu=84.51N/mm2L=2.857mm

Please log in to add an answer.