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Find the maximum and minimum stress produced in a straight bar as shown in fig due to axially applied load of 12kN.
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written 6.1 years ago by
teamques10
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• modified 6.0 years ago |
$A_1 = \frac{\pi}{4}\hspace{0.05cm}\times\hspace{0.05cm}12^2 = 113.04\hspace{0.05cm}mm^2$
$A_2 = \frac{\pi}{4}\hspace{0.05cm}\times\hspace{0.05cm}25^2 = 490.87\hspace{0.05cm}mm^2$
$\sigma{max} = \frac{W}{A_1} = \frac{12\hspace{0.05cm}\times\hspace{0.05cm}10^3}{113.04} = 106.15\hspace{0.05cm}N/mm^2$
$\sigma{min} = \frac{W}{A_2} = \frac{12\hspace{0.05cm}\times\hspace{0.05cm}10^3}{49.87} = 24.44\hspace{0.05cm}N/mm^2$
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