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Hub diameter of Kapilan turbine working under head of 12m is 0.35 times diameter of runner. The turbine is running at 100 rpm. Vane angle of extreme edge of runner outlet is 15 and flow ratio 0.6
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Given:- H=12m, hub dia Db=0.35×runner diaD

N=100 rpm ϕ=15

flow ratio kf=vf12gH=0.6

vf1=0.62gH

=0.6×2×9.81×12=9.206 m/s

vf2=vf1=9.206 m/s

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vm2=0 since discharge is areial

From Outlet velocity EFG

tanϕ=vf2u2

tan15=9.206u2

u2=34.357 m/s

But u1=u2=u=34.357 m/s

i) Diameter of runner Do

u1=πDoN60

34.357=π×Do×10060

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