written 6.5 years ago by
teamques10
★ 69k
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modified 6.5 years ago
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Given
Jet veloicty v2=35m/s
vane velocity, 4=20m/s
α=30∘,β=180−120=60∘
1] Vane angle at inlet Θ and exit , ϕ
from inlet velocity △ACD
Vw=Ac=v1cosα=30.31 m/s
vs1=CD=V1sinalpha
35 sin 30=17.50m/s
BC=Vw1−μ=30.31-20=10.31m/s

vr1BD=√(BC)2+(D)2
√(10.31)2+(17.8)2
20.31 m/s
Θ=tan−1(CDBC)
tan−1(17.510.31)=59.5
Consider outlet velocity △EGH and neglecting blade friction i,e
Vr2=vr1=20.31 m/s
Applying …
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