Ask
Search
Ask Question
Login
×
×
Welcome back.
and 2 others joined a min ago.
Continue with Google
Continue with email
0
6.0k
views
Explain Voltage divider bias or self-bias
written
6.2 years ago
by
teamques10
★
69k
• modified 5.1 years ago
electronic circuits and communication
ADD COMMENT
FOLLOW
SHARE
EDIT
1 Answer
0
331
views
written
6.2 years ago
by
teamques10
★
69k
Features:
The resistors $R_1$ and $R_2$ form a potential divider to apply a fixed voltage $V_B$ to the base.
A resistance $R_E$ has been connected in the emitter circuit. This resistor is not present in the fixed bias or collector to the base bias circuit.
Base voltage $$V_B=V_{R2}=\frac{R_2}{R_1+R_2 } \times V_{CC}$$
Bias stabilization using voltage divider bias circuit
If $I_c$ increases due to change in temperature or $β_{dc}$
Then $I_E$ increases
Hence drop across $R_E$ increases $(V_E=I_E R_E )$
Hence $I_C$ also decreases. Thus the compensation for increase in $I_C$ is achieved.
ADD COMMENT
SHARE
EDIT
Please
log in
to add an answer.
Community
Users
Levels
Badges
Content
All posts
Tags
Dashboard
Company
About
Team
Privacy
Submit question paper solutions and earn money