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Fig shown an unsymmetriacal sprinkler. It has a friction less shaft and equal flow through each nozzle with velocity of 8 m/sec relative to nozzle find the speed of rotation in rpm
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enter image description here

VA=8m/s    r1=0.4m    r2=0.6m

Since wr_{2}\gt w_{r1}

Absolute Velocity

V1=VA+wr1=8+w×0.4

V2=VBwr2

=8w×0.6

Since there is no friction the moment of moment of the fluid sprinkler is zero i.e there is no external torque T=0

T=PQ(V2r2V1r1)

o=v2r2v1r1

VAR1=V2r2(8+w×0.4)0.4

$(8-w\times …

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