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Fig shown a lawn sprinkler with two jets each located at 30 cm from the center. The jets are 1 cm diameter. Assume no friction find the speed of rotation for discharge of 3 l/s
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d=1cm=0.01m

r=30cm=0.3m

Q=1 litre/sec

Qπ4×0.012

=7.854×105m2

Velocity of jet, V1=QA=3×1037.854×105=19.098m/s

Since r1=r2

Resultant Velocity VA=VA=wr

=19.098=w×0.3

w=63.66 rad/sec

Speed of rotation(N) w=2πN60

63.66=2π×N60

N=608.19 rpm

The speed of rotation is 608.19 rpm

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