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Draw the shear force diagram and bending moment diagram and axial diagram/ thrust diagram for the beam loaded as shown in fig.

A simply supported beam carries inclined loads 100 N, 200 N, and 300 N inclined at 30 degree, 45 degree and 60 degree to the vertical as shown in fig. These loads act at 1m, 2m and 3m from the left support respectively. If the span is 4m. part 1 of 1 Draw the Shear Force, Bending Moment and Thrust (Axial Force) Diagrams.

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The inclined forces are resolved into vertical and horizontal components in fig.(a)

Now, taking moment about hinged end A

Vb4=(86.61)+(141.42)+(1503)

Vb=204.85NandVa=(86.6+141.4+150)204.85=173.15N

Resolving Horizontally,

Ha=50+141.4+259.8

Ha=451.20N

SF analysis:

SF at any section in AC=173.15N

SF at any section in CD=173.1586.6=86.55N

SF at any section in DE=150204.85=54.85N

SF at any section in EB=204.85N.

BM analysis :

BMA=0

BMB=0

BMC=173.151=173.15Nm

BMD=(173.152)(86.61)=259.7Nm

BME=204.851=204.85Nm

Thrust analysis: OR Axial face analysis:

Thrust at any section in AC=451.2N

Thrust at any Section in CD=451.250=401.2N

Thrust at any Section in DE=259.8N

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part 1 of 1 part 2 of 2

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