Draw the shear force diagram and bending moment diagram for the beam loaded as shown in fig.

And locate the point contra flexure ( if any).

Let $V_A$ and $V_B$ be the support reaction at A and B respectively

$\sum F_y=0 (+ve)$

$V_A+V_B=8*4+10=42$ (1)

$\sum M_B=0 (+ve)$

$V_A*(4+5)-8*4*(\frac{4}{2}+5)+10*3=0$

$V_A=21.55KN$

$V_B=42-21.55=20.45KN$

Shear force analysis:

SF @ A=21.55KN

SF @ C=21.55-8*4=-10.45KN

SF @ B but just on LHS of B=-10.45KN

SF @ B but just on RHS of …